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6^4-6x^2+8=0
We add all the numbers together, and all the variables
-6x^2+1304=0
a = -6; b = 0; c = +1304;
Δ = b2-4ac
Δ = 02-4·(-6)·1304
Δ = 31296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{31296}=\sqrt{64*489}=\sqrt{64}*\sqrt{489}=8\sqrt{489}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{489}}{2*-6}=\frac{0-8\sqrt{489}}{-12} =-\frac{8\sqrt{489}}{-12} =-\frac{2\sqrt{489}}{-3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{489}}{2*-6}=\frac{0+8\sqrt{489}}{-12} =\frac{8\sqrt{489}}{-12} =\frac{2\sqrt{489}}{-3} $
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